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1-0.75x+0.125x^2=0
a = 0.125; b = -0.75; c = +1;
Δ = b2-4ac
Δ = -0.752-4·0.125·1
Δ = 0.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{0.0625}}{2*0.125}=\frac{0.75-\sqrt{0.0625}}{0.25} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{0.0625}}{2*0.125}=\frac{0.75+\sqrt{0.0625}}{0.25} $
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